拓展
现在已经编写了 push 和 pop,其他所有内容都与堆栈大小写完全相同。只有改变列表长度的操作才需要真正担心尾指针。
因此,让我们从第二个列表中窃取所有这些内容(确保反转预期的测试输出) :
// ...
pub struct IntoIter<T>(List<T>);
pub struct Iter<'a, T> {
next: Option<&'a Node<T>>,
}
pub struct IterMut<'a, T> {
next: Option<&'a mut Node<T>>,
}
impl<T> List<T> {
// ...
pub fn peek(&self) -> Option<&T> {
self.head.as_ref().map(|node| {
&node.elem
})
}
pub fn peek_mut(&mut self) -> Option<&mut T> {
self.head.as_mut().map(|node| {
&mut node.elem
})
}
pub fn into_iter(self) -> IntoIter<T> {
IntoIter(self)
}
pub fn iter(&self) -> Iter<'_, T> {
Iter { next: self.head.as_ref().map(|node| &**node) }
}
pub fn iter_mut(&mut self) -> IterMut<'_, T> {
IterMut { next: self.head.as_mut().map(|node| &mut **node) }
}
}
impl<T> Drop for List<T> {
fn drop(&mut self) {
let mut cur_link = self.head.take();
while let Some(mut boxed_node) = cur_link {
cur_link = boxed_node.next.take();
}
}
}
impl<T> Iterator for IntoIter<T> {
type Item = T;
fn next(&mut self) -> Option<Self::Item> {
self.0.pop()
}
}
impl<'a, T> Iterator for Iter<'a, T> {
type Item = &'a T;
fn next(&mut self) -> Option<Self::Item> {
self.next.map(|node| {
self.next = node.next.as_ref().map(|node| &**node);
&node.elem
})
}
}
impl<'a, T> Iterator for IterMut<'a, T> {
type Item = &'a mut T;
fn next(&mut self) -> Option<Self::Item> {
self.next.take().map(|node| {
self.next = node.next.as_mut().map(|node| &mut **node);
&mut node.elem
})
}
}
#[cfg(test)]
mod test {
// ...
#[test]
fn into_iter() {
let mut list = List::new();
list.push(1); list.push(2); list.push(3);
let mut iter = list.into_iter();
assert_eq!(iter.next(), Some(1));
assert_eq!(iter.next(), Some(2));
assert_eq!(iter.next(), Some(3));
assert_eq!(iter.next(), None);
}
#[test]
fn iter() {
let mut list = List::new();
list.push(1); list.push(2); list.push(3);
let mut iter = list.iter();
assert_eq!(iter.next(), Some(&1));
assert_eq!(iter.next(), Some(&2));
assert_eq!(iter.next(), Some(&3));
assert_eq!(iter.next(), None);
}
#[test]
fn iter_mut() {
let mut list = List::new();
list.push(1); list.push(2); list.push(3);
let mut iter = list.iter_mut();
assert_eq!(iter.next(), Some(&mut 1));
assert_eq!(iter.next(), Some(&mut 2));
assert_eq!(iter.next(), Some(&mut 3));
assert_eq!(iter.next(), None);
}
}
> cargo test
Running target/debug/lists-5c71138492ad4b4a
running 15 tests
test fifth::test::into_iter ... ok
test fifth::test::basics ... ok
test fifth::test::iter ... ok
test fifth::test::iter_mut ... ok
test first::test::basics ... ok
test fourth::test::basics ... ok
test fourth::test::into_iter ... ok
test fourth::test::peek ... ok
test second::test::basics ... ok
test second::test::into_iter ... ok
test second::test::iter ... ok
test second::test::iter_mut ... ok
test second::test::peek ... ok
test third::test::basics ... ok
test third::test::iter ... ok
test result: ok. 11 passed; 0 failed; 0 ignored; 0 measured
复制粘贴。
一开始我以为我们得搞乱IntoIter,但我们还是很方便地按迭代顺序弹出!
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